Question

June 17, 2021

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Answer

In vertex form, the equation need be transformed as , for instance a function of x

f(x) =(a-h)^2+k , the parabola’s vertex is given by the (h,k),

y=9x^2+9x-1,

y=9(x^2+x)-1, we need to find the roots of the equation in the brackets, that is, (x^2+x),

y=9((x+1/2) ^2 -9/4-1

y=9(x+1/2) ^2-13/4 , the vertex form of the equation

Which equation is y = 9x2 + 9x – 1 rewritten in vertex form?

y = 9x2 + 9x – 1

y+ = 9(x2 + x + ) -1

y+ 9(1/2)2 = 9(x2 + x + (1/2)2 - 1

y+ 9/4 = 9(x2 + x +1/4) – 1

y = 9(x2 + x +1/4) -1-9/4

y = 9(x2 + ½)2 – 13/4

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