# Calculate the wavelength of an electron (m = 9.11 × 10-28 g) moving at 3.66 × 106 m/s.

A. 1.99 x 10-10 m

B. 5.03 x 10-10 m

C. 1.81 x 10-10 m

D. 5.52 x 10-9 m

E. 2.76 x 10-9 m

** "A-1.99 x 10^-10 m."** The rule of De Broglie will be utilized to solve this question, which asserts that "Planck's constant" when divided by momentum is lambda. Since momentum is equal to the mass and velocity product, lambda equals "Planck's constant" divided by the mass-velocity product. For this situation, h, "Planck's constant" is 6.63 time 10 raised to -34, mass is 9.11 x 10^-28 x 10^-3 kg, and velocity is 3.66 x 10^6 meter/sec. To obtain wavelength, substitute the following into De Broglie's equation: lambda = (6.63 x 10^-34) / (9.11 x 10^-28 x 10^-3 x 3.66 x 10^6). Therefore, the answer is 1.99 x 10^-10 m.

With considerations that momentum = mass * velocity therefore, Lambda = Planck's constant / (mass * velocity). Therefore, P (representing Planck's constant) =6.633 * 10^-34. Mass = 9.11 * 10^-28 * 10^-3 kg. Therefore, velocity = 3.66 * 10^6 meter/sec

Answer ** A)1.99 x 10-10m**: This is because to get the answer, we use De Broglie's rule, which states that: lambda = Planck's.